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By M. L. Balinski

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0/50. The question here is how do you determine which page to replace? In theory, either page is a valid target, both containing the same numerical weight for potential replacement. Texture A has a higher cost, and thus would be more expensive to replace if it were needed in the next frame. Texture B has a lower cost, but has an APC value of 100%, so there’s a high probability that this page will be needed immediately. In practice, I’ve found that biasing this decision to replace a lower APC when multiple pages return the same value works much better.

Combining ideas from the previously described work and adding our little gem, we arrive at our solution. Our Solution Our solution uses a hybrid approach, whereby we split our allocator in two parts— one handling small allocations and the other handling the rest. Small Allocator The minimum and maximum small allocations are configurable and are set by default to 8 and 256 bytes, respectively. 1. 1 Selection of the appropriate bin based upon allocation size. 2 High Performance Heap Allocator 17 Notice that since the small allocations are arranged into bins of specific sizes, you can keep any size-related information just once for the whole bin, instead of with every allocation.

A use count determines when the page is completely empty, and a bin index determines which bin this page belongs to. Most importantly, all pages that belong to the same bin are linked in a doubly-linked list, so that you can easily add, remove, or arrange pages. The last piece of the puzzle is almost straightforward—during a free operation, the provided payload address is aligned with the page boundary. 2. 2 The layout of a single page in a bin. 18 Section 1 General Programming This method places the bookkeeping information at the back of the page, as opposed to the front, because there is often a small piece of remaining memory at the back, due to the page size not being exactly divisible by the element size.

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